Question:

Mr. Suresh went into a restaurant and had a lunch worth Rs. 162. He paid using a 500 rupee note. Happy with the meal, he then bought a mini snack box for Rs. 37 and paid using a 100 rupee note. In both cases, Suresh collected his balance change from the cashier, and he did not pay any tips. The next day, when the cashier deposited the money in the bank, the banker found that only the two currency notes given by Suresh were counterfeit. As per policy, the bank tore up both notes on the spot. What is the total loss to the restaurant in this transaction?

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Add up both the change given back and the value of food and snack served.
Updated On: Jul 30, 2026
  • 1200
  • 600
  • 7991
  • None of the above
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The Correct Option is B

Approach Solution - 1

To determine the total loss to the restaurant through Mr. Suresh's transaction, we need to evaluate each of the transactions he made step-by-step.

  1. Suresh had a lunch worth Rs. 162 and paid using a 500 rupee note.
  2. Suresh then collected his balance change, which would be Rs. 500 - Rs. 162 = Rs. 338.
  3. Later, he bought a mini snack box for Rs. 37 and paid using a 100 rupee note.
  4. He collected his balance change here as well, which would be Rs. 100 - Rs. 37 = Rs. 63.

Let's summarize the transactions:

  1. Suresh paid Rs. 500 for the first transaction, collected Rs. 338 as change, effectively costing the restaurant Rs. 162 worth of food.
  2. Suresh paid Rs. 100 for the second transaction, collected Rs. 63 as change, effectively costing the restaurant Rs. 37 worth of food.

Total amount received by the restaurant from Suresh:

  • First transaction: Rs. 500 (received) - Rs. 338 (change given) = Rs. 162.
  • Second transaction: Rs. 100 (received) - Rs. 63 (change given) = Rs. 37.

Total received: Rs. 162 + Rs. 37 = Rs. 199.

Since both currency notes (Rs. 500 note and Rs. 100 note) provided by Suresh were counterfeit, the total monetary value of the notes actually received by the restaurant was Rs. 0.

However, the restaurant had already given away Rs. 338 and Rs. 63 as change, totaling to:

  • Rs. 338 (first transaction change) + Rs. 63 (second transaction change) = Rs. 401.

The loss incurred by the restaurant is, therefore, the amount of valid currency given as change minus any real incoming value, which is:

Loss = Change Given - Value of Food = Rs. 401 (change) + Rs. 199 (value of food served) = Rs. 600.

Hence, the total loss to the restaurant is Rs. 600, consistent with the correct answer given in the options.

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Approach Solution -2

Step 1: Work out the change the restaurant handed back each time.
For the lunch: Suresh paid Rs. 500 for a Rs. 162 meal, so the cashier gave back \(500-162=338\) in change. For the snack: he paid Rs. 100 for a Rs. 37 snack, so the change was \(100-37=63\).

Step 2: Understand what the restaurant actually lost.
Both notes, the 500 and the 100, turned out to be fake and were destroyed, so the restaurant received zero real money from Suresh in either transaction. It still handed over real food and a real snack, and real change from its own cash box.

Step 3: Add up the value the restaurant gave away for nothing.
The restaurant lost the value of the goods served, \(162+37=199\), plus the real change it paid out, \(338+63=401\).

Step 4: Add these two parts for the total loss.
Total loss = \(199+401=600\).

Final Answer:
The restaurant's total loss is Rs. 600. \[ \boxed{Rs.\ 600} \]
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