Question:
Mole fraction of H$_2$SO$_4$ in aqueous solution is 0.9. Find mass % of H$_2$SO$_4$. (H=1, S=32, O=16 u)
Mole fraction of H$_2$SO$_4$ in aqueous solution is 0.9. Find mass % of H$_2$SO$_4$. (H=1, S=32, O=16 u)
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Convert mole fraction to moles, then calculate masses, finally use mass percent formula.
Updated On: Mar 6, 2026
- 90
- 85
- 98
- 80
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The Correct Option is C
Solution and Explanation
Mole fraction $x_\text{H2SO4}=0.9$. Let 1 mole solution → 0.9 mol H$_2$SO$_4$, 0.1 mol H$_2$O. Mass H$_2$SO$_4$ = $0.9\times 98 = 88.2$ g, mass H$_2$O = $0.1 \times 18 = 1.8$ g. Mass % = $88.2/90 \times 100 \approx 98%$.
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