Minimum energy required to take out the only one electron from ground state of He\(^+\) is
Show Hint
- \(13.6\ \mathrm{eV}\)
- \(54.4\ \mathrm{eV}\)
- \(27.2\ \mathrm{eV}\)
- \(6.8\ \mathrm{eV}\)
The Correct Option is B
Solution and Explanation
For hydrogen-like atoms, ionization energy \(E = 13.6 Z^2\ \mathrm{eV}\).
Step 2: Detailed Explanation:
For He\(^+\), Z = 2
\(E = 13.6 \times (2)^2 = 13.6 \times 4 = 54.4\ \mathrm{eV}\)
Step 3: Final Answer:
Minimum energy required is 54.4 eV.
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