Question

Match the type of equilibrium with typical examples:

List I	List II
A. Oxidation/Reduction Equilibrium (Kredox) --- III. MnO4- + 5Fe2+ + 8H+ ⇌ Mn2+ + 5Fe3+ + 4H2O B. Heterogeneous Equilibrium (Ksp) --- IV. BaSO4(s) ⇌ Ba2+ + SO4 2- C. Distribution Equilibrium (Kd) --- I. I2(aq) ⇌ I2(org) D. Dissociation of weak Acid (Ka) --- II. CH3COOH + H2O ⇌ H3O+ + CH3COO-	III. MnO4- + 5Fe2+ + 8H+ ⇌ Mn2+ + 5Fe3+ + 4H2O IV. BaSO4(s) ⇌ Ba2+ + SO4 2- I. I2(aq) ⇌ I2(org) II. CH3COOH + H2O ⇌ H3O+ + CH3COO-

• A. A-IV, B-III, C-I, D-II
• B. A-III, B-I, C-IV, D-II
• C. A-III, B-IV, C-II, D-I
• D. A-III, B-IV, C-I, D-II

Hint:

Identify reaction type: electron transfer $\rightarrow$ redox; solid dissolving $\rightarrow$ $K_{sp}$; two liquid phases $\rightarrow$ $K_d$; partial ionisation of acid $\rightarrow$ $K_a$.

Answer 1

The Correct Option is D

Step 1: Concept
Types of chemical equilibrium and their representative reactions.

Step 2: Meaning
Redox equilibrium ($K_{\text{redox}}$): involves electron transfer.
Heterogeneous equilibrium ($K_{sp}$): involves different physical states.
Distribution equilibrium ($K_d$): describes partitioning between two immiscible phases.
Weak acid dissociation ($K_a$): partial ionisation of a weak acid.

Step 3: Analysis
A (Redox) --- III: MnO$_4^-$/Fe$^{2+}$ reaction involves change in oxidation states.
B ($K_{sp}$) --- IV: BaSO$_4$(s) dissolving into ions involves solid/liquid phases.
C ($K_d$) --- I: I$_2$ partitioning between aqueous and organic phase.
D ($K_a$) --- II: Acetic acid partial dissociation in water.

Step 4: Conclusion
Correct matching: A-III, B-IV, C-I, D-II. Final Answer: (D)