Question

Match the LIST-I with LIST-II:

List-I		List-II
A.	Planck's constant	I.	ML2T-2
B.	Stopping potential	II.	T-1
C.	Work function	III.	ML2T-2A-1
D.	Threshold frequency	IV.	ML2T-3A-1

Choose the correct answer from the options given below:

• A. A-III, B-IV, C-I, D-II
• B. A-I, B-II, C-III, D-IV
• C. A-IV, B-III, C-I, D-II
• D. A-I, B-IV, C-III, D-II

Hint:

Remember:

• Energy: \[ ML^2T^{-2} \]
• Potential: \[ ML^2T^{-3}A^{-1} \]
• Frequency: \[ T^{-1} \]
• Planck’s constant: \[ ML^2T^{-1} \]

Answer 1

The Correct Option is A

Concept: To match physical quantities with dimensions, we use standard dimensional formulas.

• Energy: \[ [E] = ML^2T^{-2} \]
• Frequency: \[ [\nu] = T^{-1} \]
• Potential difference: \[ [V] = ML^2T^{-3}A^{-1} \]
• Planck’s constant: \[ h = \frac{E}{\nu} \]

Step 1: Find dimensions of Planck’s constant. Using: \[ h = \frac{E}{\nu} \] \[ [h] = \frac{ML^2T^{-2}}{T^{-1}} \] \[ [h] = ML^2T^{-1} \] Thus: \[ A \rightarrow III \]

Step 2: Find dimensions of stopping potential. Stopping potential is a potential difference. Dimensions of potential: \[ [V] = ML^2T^{-3}A^{-1} \] Thus: \[ B \rightarrow IV \]

Step 3: Find dimensions of work function. Work function is energy required to remove an electron. Dimensions: \[ [W] = ML^2T^{-2} \] Thus: \[ C \rightarrow I \]

Step 4: Find dimensions of threshold frequency. Frequency has dimensions: \[ [\nu] = T^{-1} \] Thus: \[ D \rightarrow II \] Hence, the correct matching is: \[ A-III,\quad B-IV,\quad C-I,\quad D-II \] Therefore, \[ \boxed{A\text{-}III,\; B\text{-}IV,\; C\text{-}I,\; D\text{-}II} \]