Question:

Match the LIST-I with LIST-II - Let $A = \begin{bmatrix} 1 & 0 \\ 5 & 2 \end{bmatrix}$. Then
Choose the correct answer from the options given below:

Show Hint

For any triangular matrix (upper or lower), you can read the eigenvalues directly off the main diagonal!
Updated On: Jul 29, 2026
  • A-III, B-I, C-II, D-IV
  • A-III, B-I, C-IV, D-II
  • A-II, B-III, C-IV, D-I
  • A-III, B-IV, C-II, D-I
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1 : Concept:
This matching question involves computing the trace, determinant, characteristic polynomial, and eigenvalues of a $2 \times 2$ matrix.

Step 2 : Key Formulas and Approach:

For $A = \begin{bmatrix} a & b
c & d \end{bmatrix}$: 1. $\text{Trace}(A) = a + d$ 2. $\det(A) = ad - bc$ 3. Characteristic polynomial: $p(\lambda) = \det(\lambda I - A) = \lambda^2 - \text{Trace}(A)\lambda + \det(A)$ 4. Eigenvalues of a triangular matrix are its diagonal entries.

Step 3 : Step-by-step Explanation:


Item A:
$\text{Trace}(A) = \text{Sum of diagonal elements} = 1 + 2 = 3$. Matches with III.

Item B:
$\det(A) = (1)(2) - (0)(5) = 2$. Matches with I.

Item C:
$\det(\lambda I - A) = \lambda^2 - \text{Trace}(A)\lambda + \det(A) = \lambda^2 - 3\lambda + 2$. Matches with IV.

Item D:
Since $A = \begin{bmatrix} 1 & 0
5 & 2 \end{bmatrix}$ is lower triangular, its eigenvalues are the diagonal entries $1$ and $2$. Matches with II.

Step 4 : Final Answer:

The correct matching is A-III, B-I, C-IV, D-II, which corresponds to option (B).
Was this answer helpful?
0
0