Question

Match the following. \[ \begin{array}{ll} \text{I. Mustard} & \text{A. Superior} \text{II. Ray florets of sunflower} & \text{B. Half inferior/superior} \text{III. Pea} & \text{C. Inferior} \text{IV. China rose} & \text{D. Superior} \end{array} \] \[ \begin{array}{ll} \text{P. Parietal} & \text{Q. Basal} \text{R. Marginal} & \text{S. Axile} \end{array} \]

• A. I-C-Q, II-D-P, III-B-R, IV-A-S
• B. I-D-P, II-C-Q, III-B-R, IV-A-S
• C. I-D-P, II-C-Q, III-A-S, IV-B-R
• D. I-D-P, II-A-S, III-C-Q, IV-B-R

Hint:

Remember: Mustard $\rightarrow$ Parietal, Pea $\rightarrow$ Marginal, China Rose $\rightarrow$ Axile, Sunflower $\rightarrow$ Basal placentation.

Answer 1

The Correct Option is B

Concept: Different flowering plants exhibit characteristic ovary positions and placentation patterns. Identification of these features is important for plant classification.

Step 1: Mustard.
Mustard belongs to family Brassicaceae. \[ \text{Ovary = Superior} \] \[ \text{Placentation = Parietal} \] Therefore: \[ \boxed{\text{Mustard } \rightarrow D-P} \]

Step 2: Sunflower ray florets.
Sunflower belongs to family Asteraceae. \[ \text{Ovary = Inferior} \] \[ \text{Placentation = Basal} \] Thus: \[ \boxed{\text{Sunflower } \rightarrow C-Q} \]

Step 3: Pea.
Pea belongs to Fabaceae. \[ \text{Placentation = Marginal} \] Hence: \[ \boxed{\text{Pea } \rightarrow B-R} \]

Step 4: China Rose.
China rose possesses: \[ \text{Superior ovary} \] \[ \text{Axile placentation} \] Thus: \[ \boxed{\text{China rose } \rightarrow A-S} \] Combining all matches: \[ \boxed{\text{I-D-P,\; II-C-Q,\; III-B-R,\; IV-A-S}} \] Hence option (B) is correct.