Question

Match the columns: 

Column - I		Column - II
(A)	\[ \mathrm{CH_2=CH-CH_2Cl} \]	(p)	gem-Dichloride
(B)	\[ \mathrm{CH_2=CHX} \]	(q)	Vinylic halide
(C)	\[ \mathrm{CH_3CHCl_2} \]	(r)	vic-Dichloride
(D)	\[ \mathrm{CH_2ClCH_2Cl} \]	(s)	Allylic halide

• A. \(A \to (r),\ B \to (q),\ C \to (p),\ D \to (s)\)
• B. \(A \to (q),\ B \to (p),\ C \to (s),\ D \to (r)\)
• C. \(A \to (s),\ B \to (q),\ C \to (p),\ D \to (r)\)
• D. \(A \to (r),\ B \to (p),\ C \to (s),\ D \to (q)\)

Hint:

gem-dihalide: \[ \text{Both halogens on same carbon} \] vic-dihalide: \[ \text{Halogens on adjacent carbons} \]

Answer 1

The Correct Option is C

Step 1: Identify compound (A).
\[ \mathrm{CH_2=CH-CH_2Cl} \] contains halogen adjacent to double bond. Hence it is: \[ \text{allylic halide} \] Thus: \[ A\to(s) \]

Step 2: Identify compound (B).
\[ \mathrm{CH_2=CHX} \] has halogen directly attached to double bonded carbon. Hence: \[ \text{vinylic halide} \] Thus: \[ B\to(q) \]

Step 3: Identify compound (C).
\[ \mathrm{CH_3CHCl_2} \] has both chlorine atoms attached to same carbon. Hence: \[ \text{gem-dichloride} \] Thus: \[ C\to(p) \]

Step 4: Identify compound (D).
\[ \mathrm{CH_2ClCH_2Cl} \] has chlorine atoms attached to adjacent carbons. Hence: \[ \text{vic-dichloride} \] Thus: \[ D\to(r) \]

Step 5: Final matching.
\[ A\to(s),\qquad B\to(q),\qquad C\to(p),\qquad D\to(r) \] Therefore: \[ \boxed{ \mathrm{ (C)\ A \to (s),\ B \to (q),\ C \to (p),\ D \to (r) } } \]