Question:

Match the column-I with column-II Column-I & & Column-II &
(i) Friedel craft reaction & & (P) Electrophilic substitution
(ii) Williamson’s ether synthesis & & (Q) Nucleophilic substitution
(iii) Chlorination of alkane in presence of sunlight & & (R) Free radical substitution
(iv) \(Br_2/CHCl_3\) & & (S) Electrophilic addition
\endtabular \endcenter

Updated On: Apr 5, 2026
  • i$\rightarrow$R, ii$\rightarrow$S, iii$\rightarrow$Q, iv$\rightarrow$P
  • i$\rightarrow$Q, ii$\rightarrow$P, iii$\rightarrow$R, iv$\rightarrow$S
  • i$\rightarrow$P, ii$\rightarrow$Q, iii$\rightarrow$S, iv$\rightarrow$R
  • i$\rightarrow$P, ii$\rightarrow$Q, iii$\rightarrow$R, iv$\rightarrow$S
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Concept: Different organic reactions follow characteristic mechanisms.
Step 1:
Friedel–Craft reaction Friedel–Craft alkylation/acylation occurs through an electrophile attacking an aromatic ring. \[ \text{Electrophilic substitution} \] \[ (i) \rightarrow (P) \]
Step 2:
Williamson’s ether synthesis Formation of ethers occurs through \(S_N2\) reaction between alkoxide ion and alkyl halide. \[ \text{Nucleophilic substitution} \] \[ (ii) \rightarrow (Q) \]
Step 3:
Chlorination of alkanes in sunlight This proceeds via free radical chain mechanism. \[ (iii) \rightarrow (R) \]
Step 4:
Reaction with \(Br_2/CHCl_3\) Addition of bromine across a double bond proceeds through electrophilic addition. \[ (iv) \rightarrow (S) \]
Step 5:
Final matching \[ i \rightarrow P,\quad ii \rightarrow Q,\quad iii \rightarrow R,\quad iv \rightarrow S \]
Was this answer helpful?
0
0

Top JEE Main Questions

View More Questions