Question:
Match List-I with List-IIList-I (Name of the Compounds) List-II (Chemical Structures) (A) Gluconic acid (I) 
(B) Fructose (II) 
(C) Tryptophan (III) 
(D) Saccharic acid (IV) 
Choose the correct answer from the options given below:
Match List-I with List-II
Choose the correct answer from the options given below:
| List-I (Name of the Compounds) | List-II (Chemical Structures) |
|---|---|
| (A) Gluconic acid | (I) |
| (B) Fructose | (II) |
| (C) Tryptophan | (III) |
| (D) Saccharic acid | (IV) |
Show Hint
Gluconic acid: COOH at one end only. Saccharic acid: COOH at both ends. Fructose: ketone group. Tryptophan: indole ring.
Updated On: Oct 1, 2026
- (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
- (A) - (II), (B) - (I), (C) - (III), (D) - (IV)
- (A) - (III), (B) - (II), (C) - (IV), (D) - (I)
- (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Read the four structures.
Structure (I) has COOH at both ends of a 4-carbon chain of CHOH groups. Structure (II) is an amino acid with an indole ring. Structure (III) has COOH at the top and CH2OH at the bottom. Structure (IV) has a C=O (ketone) at position 2 with CH2OH at both ends. Note that the figure in the paper labels the structures in the order shown in the table.
Step 2: Match (A) Gluconic acid.
Gluconic acid is made by oxidising only the CHO group of glucose to COOH. The other end stays CH2OH. That is the structure with COOH on top and CH2OH at the bottom, structure (III). So A - III.
Step 3: Match (B) Fructose.
Fructose is a ketohexose with the ketone group at C2 and CH2OH at C1 and C6. That is structure (IV). So B - IV.
Step 4: Match (C) Tryptophan.
Tryptophan is an amino acid with an indole side chain. Only structure (II) shows an amino acid with an indole ring. So C - II.
Step 5: Match (D) Saccharic acid.
Saccharic acid is formed when both the CHO and the CH2OH ends of glucose are oxidised to COOH (nitric acid oxidation). That is structure (I). So D - I.
Step 6: Compare with the options.
We have A - III, B - IV, C - II, D - I. This is option 4. Options 1, 2 and 3 each place at least one wrong pair, for example fructose with the amino acid or tryptophan with a sugar acid.
Final Answer:
The correct matching is A - III, B - IV, C - II, D - I, which is option (4). \[ \boxed{\text{(A)-(III), (B)-(IV), (C)-(II), (D)-(I)}} \]
Structure (I) has COOH at both ends of a 4-carbon chain of CHOH groups. Structure (II) is an amino acid with an indole ring. Structure (III) has COOH at the top and CH2OH at the bottom. Structure (IV) has a C=O (ketone) at position 2 with CH2OH at both ends. Note that the figure in the paper labels the structures in the order shown in the table.
Step 2: Match (A) Gluconic acid.
Gluconic acid is made by oxidising only the CHO group of glucose to COOH. The other end stays CH2OH. That is the structure with COOH on top and CH2OH at the bottom, structure (III). So A - III.
Step 3: Match (B) Fructose.
Fructose is a ketohexose with the ketone group at C2 and CH2OH at C1 and C6. That is structure (IV). So B - IV.
Step 4: Match (C) Tryptophan.
Tryptophan is an amino acid with an indole side chain. Only structure (II) shows an amino acid with an indole ring. So C - II.
Step 5: Match (D) Saccharic acid.
Saccharic acid is formed when both the CHO and the CH2OH ends of glucose are oxidised to COOH (nitric acid oxidation). That is structure (I). So D - I.
Step 6: Compare with the options.
We have A - III, B - IV, C - II, D - I. This is option 4. Options 1, 2 and 3 each place at least one wrong pair, for example fructose with the amino acid or tryptophan with a sugar acid.
Final Answer:
The correct matching is A - III, B - IV, C - II, D - I, which is option (4). \[ \boxed{\text{(A)-(III), (B)-(IV), (C)-(II), (D)-(I)}} \]
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