Match List - I with List - II.
List - I (Saccharides) List - II (Glycosidic linkages found)
(A) Sucrose (I) \( \alpha 1 - 4 \)
(B) Maltose (II) \( \alpha 1 - 4 \) and \( \alpha 1 - 6 \)
(C) Lactose (III) \( \alpha 1 - \beta 2 \)
(D) Amylopectin (IV) \( \beta 1 - 4 \)
Choose the correct answer from the options given below:
Match List - I with List - II.
List - I (Saccharides) List - II (Glycosidic linkages found)
(A) Sucrose (I) \( \alpha 1 - 4 \)
(B) Maltose (II) \( \alpha 1 - 4 \) and \( \alpha 1 - 6 \)
(C) Lactose (III) \( \alpha 1 - \beta 2 \)
(D) Amylopectin (IV) \( \beta 1 - 4 \)
Choose the correct answer from the options given below:
Show Hint
- (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
- (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
The Correct Option is B
Solution and Explanation
- Sucrose consists of glucose and fructose linked by an \( \alpha 1-4 \) glycosidic bond, so it matches with (I).
- Maltose has two glucose units connected by an \( \alpha 1-4 \) bond, and it also has the possibility of forming a linkage with \( \alpha 1-6 \), which matches with (II).
- Lactose is a disaccharide formed from one molecule of glucose and one of galactose, with an \( \alpha 1-\beta 2 \) glycosidic bond, so it matches with (III).
- Amylopectin is a highly branched polymer of glucose with \( \beta 1-4 \) linkages in its chains, so it matches with (IV).
Thus, the correct matching is (A)-(I), (B)-(II), (C)-(III), (D)-(IV).
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