Match List - I with List - II.
List - I (Ore) List - II (Element Present) (a) Kernite (i) Tin (b) Cassiterite (ii) Boron (c) Calamine (iii) Fluorine (d) Cryolite (iv) Zinc
Choose the most appropriate answer from the options given below :
| List - I (Ore) | List - II (Element Present) | ||
| (a) | Kernite | (i) | Tin |
| (b) | Cassiterite | (ii) | Boron |
| (c) | Calamine | (iii) | Fluorine |
| (d) | Cryolite | (iv) | Zinc |
Choose the most appropriate answer from the options given below :
Show Hint
- (a) \(\to\) (i), (b) \(\to\) (iii), (c) \(\to\) (iv), (d) \(\to\) (ii)
- (a) \(\to\) (iii), (b) \(\to\) (i), (c) \(\to\) (ii), (d) \(\to\) (iv)
- (a) \(\to\) (ii), (b) \(\to\) (i), (c) \(\to\) (iv), (d) \(\to\) (iii)
- (a) \(\to\) (ii), (b) \(\to\) (iv), (c) \(\to\) (i), (d) \(\to\) (iii)
The Correct Option is C
Solution and Explanation
Cassiterite is \(\mathrm{SnO_2}\), so (b) \(\to\) (i) Tin.
Calamine is \(\mathrm{ZnCO_3}\), so (c) \(\to\) (iv) Zinc.
Cryolite is \(\mathrm{Na_3AlF_6}\), so (d) \(\to\) (iii) Fluorine.
The combination (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii) is option (3).
Answer: (3) (a) \(\to\) (ii), (b) \(\to\) (i), (c) \(\to\) (iv), (d) \(\to\) (iii)
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