Question

Match List-I with List-Il:

	List-I		List-II
A.	Coke	I.	Carbon atoms are sp3 hybridized.
B.	Diamond	II.	Used as a dry lubricant.
C.	Fullerene	III.	Used as a reducing agent.
D.	Graphite	IV.	Cage like molecules

Choose the correct answer from the options given below:

• A. A-lV, B-I, C-II, D-III
• B. A-III, B-I, C-IV, D-II
• C. A-llI, B-IV, C-I, D-II
• D. A-II, B-IV, C-I, D-III

Answer 1

The Correct Option is B

To solve the given problem, we need to match the items in List-I with their corresponding descriptions in List-II based on the properties of those substances. 

	List-I		List-II
A.	Coke	I.	Carbon atoms are sp3 hybridized.
B.	Diamond	II.	Used as a dry lubricant.
C.	Fullerene	III.	Used as a reducing agent.
D.	Graphite	IV.	Cage like molecules

Let's match each item:

1. Coke: Used as a reducing agent, typically in metallurgical processes. Therefore, Coke matches with III.
2. Diamond: In diamond, carbon atoms are sp³ hybridized and form a very hard structure. Thus, Diamond matches with I.
3. Fullerene: Fullerene molecules have a cage-like structure. Hence, Fullerene corresponds with IV.
4. Graphite: Known for its layered structure, Graphite is used as a dry lubricant. So, Graphite matches with II.

Therefore, the correct matching is:

A-III, B-I, C-IV, D-II

Answer 2

Coke: In carbon reduction techniques, it serves as a reducing agent.
Diamond: Each carbon atom in a diamond is sp³ hybridized, making it an allotrope of carbon.
Fullerene: Pentagonal and hexagonal rings (a structure resembling a cage) are present in fullerene.
Graphite: Because graphite layers are joined together by feeble Vander Wall attractions, it is a soft solid.
Therefore, The correct option is (B): A-III, B-I, C-IV, D-II