Match List I with List II List I
Element detected
List II
Reagent used/ Product formed
A Nitrogen I Na2[Fe(CN)5 NO] B Sulphur II AgNO3 C Phosphorous III Fe4[Fe(CN)6]3 D Halogen IV (NH4)2 MoO4
Choose the correct answer from the options given below:
List I Element detected | List II Reagent used/ Product formed | ||
| A | Nitrogen | I | Na2[Fe(CN)5 NO] |
| B | Sulphur | II | AgNO3 |
| C | Phosphorous | III | Fe4[Fe(CN)6]3 |
| D | Halogen | IV | (NH4)2 MoO4 |
Choose the correct answer from the options given below:
- A-II, B-I, C-IV, D-III
- A-III, B-I, C-IV, D-II
- A-II, B-IV, C-I, D-III
- A-IV, B-II, C-I, D-III
The Correct Option is B
Solution and Explanation
- A: Nitrogen – Fe4[Fe(CN)6]3
- Nitrogen is detected by converting it into Prussian blue (Fe4[Fe(CN)6]3) using the Lassaigne's test.
- B: Sulphur – Na2[Fe(CN)5NO]
- Sulphur reacts to form sodium nitroprusside (Na2[Fe(CN)5NO]), which gives a violet color, indicating the presence of sulfur.
- C: Phosphorus – (NH4)2MoO4
- Phosphorus is detected as ammonium phosphomolybdate, which forms a yellow precipitate.
- D: Halogen – AgNO3
- Halogens are detected by forming a precipitate with AgNO3. The precipitate's color varies depending on the halogen: white (chloride), pale yellow (bromide), or yellow (iodide).
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