Question

Match List I with List II

	List I  Element detected		List II  Reagent used/ Product formed
A	Nitrogen	I	Na2[Fe(CN)5 NO]
B	Sulphur	II	AgNO3
C	Phosphorous	III	Fe4[Fe(CN)6]3
D	Halogen	IV	(NH4)2 MoO4

Choose the correct answer from the options given below:
 

• A. A-II, B-I, C-IV, D-III
• B. A-III, B-I, C-IV, D-II
• C. A-II, B-IV, C-I, D-III
• D. A-IV, B-II, C-I, D-III

Answer 1

The Correct Option is B

• A: Nitrogen – Fe₄[Fe(CN)₆]₃
  • Nitrogen is detected by converting it into Prussian blue (Fe₄[Fe(CN)₆]₃) using the Lassaigne's test. 
• B: Sulphur – Na₂[Fe(CN)₅NO]
  • Sulphur reacts to form sodium nitroprusside (Na₂[Fe(CN)₅NO]), which gives a violet color, indicating the presence of sulfur.
• C: Phosphorus – (NH₄)₂MoO₄
  • Phosphorus is detected as ammonium phosphomolybdate, which forms a yellow precipitate.
• D: Halogen – AgNO₃
  • Halogens are detected by forming a precipitate with AgNO₃. The precipitate's color varies depending on the halogen: white (chloride), pale yellow (bromide), or yellow (iodide).