Match List-I with List-II
List-I-Complex List-II-CFSE A [Cu(NH3)6]2+ I -0.6 B [Ti(H2O)6]3+ II -2.0 C [Fe(CN)6]3− III -1.2 D [NiF6]4- IV -0.4
Choose the correct answer from the options given below:
| List-I-Complex | List-II-CFSE | ||
| A | [Cu(NH3)6]2+ | I | -0.6 |
| B | [Ti(H2O)6]3+ | II | -2.0 |
| C | [Fe(CN)6]3− | III | -1.2 |
| D | [NiF6]4- | IV | -0.4 |
Choose the correct answer from the options given below:
- A-III, B-IV, C-I, D-II
- A-I, B-IV, C-II, D-III
- A-II, B-III, C-I, D-IV
- A-I, B-II, C-IV, D-III
The Correct Option is B
Solution and Explanation
Solution:
We need to match the complexes in List-I with their Crystal Field Stabilization Energy (CFSE) values in List-II.
Let's analyze each complex:
A. [Cu(NH3)6]2+
Cu2+ has a d9 configuration. In an octahedral field, it will have a t2g6 eg3 configuration. Due to Jahn-Teller distortion, the CFSE is not straightforward. However, for a d9 high spin configuration, it would be approximately -0.6Δo.
Therefore, A matches with I (-0.6).
B. [Ti(H2O)6]3+
Ti3+ has a d1 configuration. In an octahedral field, it will have a t2g1 eg0 configuration. The CFSE is -0.4Δo.
Therefore, B matches with IV (-0.4).
C. [Fe(CN)6]3-
Fe3+ has a d5 configuration. CN- is a strong field ligand, so it will be a low spin complex with a t2g5 eg0 configuration. The CFSE is -2.0Δo.
Therefore, C matches with II (-2.0).
D. [NiF6]4-
Ni2+ has a d8 configuration. F- is a weak field ligand, so it will be a high spin complex with a t2g6 eg2 configuration. The CFSE is -1.2Δo.
Therefore, D matches with III (-1.2).
Matching:
A - I (-0.6)
B - IV (-0.4)
C - II (-2.0)
D - III (-1.2)
Correct Answer: A-I, B-IV, C-II, D-III
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