Question:

Match List-I with List-II :
List - I(Block/group in periodic table)List - II(Element)
(A) Lanthanoid(I) Ce
(B) d-block element(II) As
(C) p-block element(III) Cs
(D) s-block element (IV) Mn
Identify the correct answer from the options given below :

Updated On: May 1, 2026
  • A-I, B-II, C-IV, D-III
  • A-I, B-IV, C-III, D-II
  • A-I, B-IV, C-II, D-III
  • A-IV, B-I, C-II, D-III
Show Solution
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The Correct Option is C

Solution and Explanation

To identify the correct matches between List-I (Block/group in periodic table) and List-II (Element), we need to understand the characteristics and classification of different blocks of elements in the periodic table: 

  1. Lanthanoid (A): Lanthanoids are elements with atomic numbers from 57 to 71. They belong to the f-block and show similar properties. Cerium (Ce) is a lanthanoid. Therefore, A-I is the correct match.
  2. d-block element (B): d-block elements are also known as transition metals. Manganese (Mn) is a well-known d-block element. Therefore, B-IV is the correct match.
  3. p-block element (C): p-block elements include groups 13 to 18 of the periodic table. Arsenic (As) is a member of the p-block elements. Therefore, C-II is the correct match.
  4. s-block element (D): s-block elements include the first two groups of the periodic table. They consist of alkali metals and alkaline earth metals. Cesium (Cs) is an alkali metal, making it an s-block element. Therefore, D-III is the correct match.

Thus, the correct matching is: A-I, B-IV, C-II, D-III.

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