Match List -I with List II:
Choose the correct answer from the options given below :
Match List -I with List II:
Choose the correct answer from the options given below :
- (A) – (IV), (B) – (III), (C) – (I), (D) – (II)
- (A) – (III), (B) – (I), (C) – (II), (D) – (IV)
- (A) – (II), (B) – (IV), (C) – (III), (D) – (I)
- (A) – (I), (B) – (II), (C) – (IV), (D) – (III)
The Correct Option is A
Approach Solution - 1
Understand the Effects (Inductive, Resonance, and Electromeric):
E Effect (Electromeric Effect): A temporary effect where a pi bond shifts to one of the atoms in the presence of an attacking reagent.
R Effect (Resonance Effect): The delocalization of electrons in a conjugated system.
+E Effect (Positive Electromeric Effect): Electron pair movement towards the attacking atom.
+R Effect (Positive Resonance Effect): Electron-donating resonance effect, often seen in groups with lone pairs that can donate electron density.
Match Each Mechanism with the Correct Effect:
- (A) Shows a nucleophile attacking and shifting a lone pair, which is a +R effect (IV).
- (B) Shows protonation that increases electron density through resonance, an R effect (II).
- (C) Shows cyanide attaching and shifting electron density, representing +E effect (III).
- (D) Shows electron density shift due to a nitro group, indicating E effect (I).
Conclusion:
The correct matching is:
\[ (A) - (IV), \, (B) - (II), \, (C) - (III), \, (D) - (I) \]
which corresponds to Option (1).
Approach Solution -2
We are required to match List I (Mechanism steps) with List II (Effect).
The options involve identifying whether each reaction step shows +R effect, −R effect, +E effect, or −E effect based on the movement of electrons and resonance behavior.
Step 2: Analyze each mechanism step.
(A) — The structure shows an −NH2 group donating electrons to the benzene ring through resonance. This results in electron release by resonance (+R effect) but an electron-withdrawing inductive effect (−E effect). The resonance dominates, so this corresponds to +R effect.
Hence, (A) → (IV).
(B) — Involves the addition of a proton to the benzene ring, leading to the development of a positive charge. This represents an electron-attracting or positive electronic effect (+E effect).
Hence, (B) → (III).
(C) — The structure involves the cyano group (−CN), which strongly withdraws electrons by its −R and −E effects. The electron flow towards the −CN group indicates a −E effect.
Hence, (C) → (I).
(D) — The nitro group (−NO2) withdraws electrons by both resonance and induction. However, when resonance delocalization of electrons is shown, it indicates a −R effect.
Hence, (D) → (II).
Step 3: Final matching.
\[ \boxed{ (A) – (IV), \, (B) – (III), \, (C) – (I), \, (D) – (II) } \]
Final Answer:
\[ (A) – (IV), \, (B) – (III), \, (C) – (I), \, (D) – (II) \]
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