Question:

Match List-I with List-II.

Show Hint

Use the pattern: \[ \sqrt{0/4}, \sqrt{1/4}, \sqrt{2/4}, \sqrt{3/4}, \sqrt{4/4} \] to quickly recall sine values of $0^\circ, 30^\circ, 45^\circ, 60^\circ, 90^\circ$.
  • a - iii, b - i, c - ii, d - iv
  • a - iv, b - ii, c - i, d - iii
  • a - iii, b - ii, c - i, d - iv
  • a - iv, b - ii, c - iii, d - i
Show Solution
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The Correct Option is A

Solution and Explanation

Concept: Trigonometric ratios for standard angles are derived from unit circle definitions and special right triangles. These values are fixed and commonly used in solving trigonometric equations and geometric problems.

Step 1: Evaluate $\sin(\pi/3)$

The angle $\frac{\pi}{3}$ corresponds to $60^\circ$. In a $30^\circ-60^\circ-90^\circ$ triangle, the sine of $60^\circ$ is: \[ \sin(60^\circ) = \frac{\sqrt{3}}{2} \] Thus, (a) matches (iii).

Step 2: Evaluate $\sin(\pi/4)$

The angle $\frac{\pi}{4}$ corresponds to $45^\circ$. In a $45^\circ-45^\circ-90^\circ$ triangle: \[ \sin(45^\circ) = \frac{1}{\sqrt{2}} \] Thus, (b) matches (i).

Step 3: Evaluate $\sin(\pi/6)$

The angle $\frac{\pi}{6}$ corresponds to $30^\circ$. In a $30^\circ-60^\circ-90^\circ$ triangle: \[ \sin(30^\circ) = \frac{1}{2} \] Thus, (c) matches (ii).

Step 4: Evaluate $\sin(\pi/2)$

The angle $\frac{\pi}{2}$ corresponds to $90^\circ$. On the unit circle: \[ \sin(90^\circ) = 1 \] Thus, (d) matches (iv).

Step 5: Final Matching

Combining all results: \[ (a,b,c,d) = (iii, i, ii, iv) \] Hence, option (A) is correct.
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