Question

Match List-I with List-II:

• A. A-I, B-II, C-III, D-IV
• B. A-I, B-III, C-II, D-IV
• C. A-III, B-IV, C-I, D-II
• D. A-I, B-II, C-IV, D-III

Answer 1

The Correct Option is C

To match List-I with List-II effectively based on the Finkelstein reaction, let's analyze each pair carefully.

List-I	List-II
A. Finkelstein Reaction	III. Nucleophilic substitution of alkyl halides leading to exchange of halogens with iodide ion
B. Swarts Reaction	IV. Replacement of halogen by fluorine using antimony trifluoride
C. Sandmeyer Reaction	I. Replacement of diazonium group in benzene diazonium salts with other atoms like halides
D. Wurtz Reaction	II. Coupling of two alkyl halides to produce alkanes using sodium

For the correct matches:

• A-III: The Finkelstein Reaction involves a nucleophilic substitution where one halide ion is replaced by another halide, typically iodine.
• B-IV: The Swarts Reaction involves fluorination, where halogens in organic molecules are replaced by fluorine, often using antimony trifluoride as a reagent.
• C-I: The Sandmeyer Reaction involves using benzene diazonium salts to introduce halides into an aromatic ring structure.
• D-II: The Wurtz Reaction involves the coupling of alkyl halides using sodium, resulting in the formation of higher alkanes.

Based on the above understanding, the correct matching is: A-III, B-IV, C-I, D-II.

Answer 2

You've accurately described each reaction and its matching reagent/product. Here's a summary for clarity:

List I - Reaction and List II - Reaction Equation/Description:

• (A) Swarts Reaction: (III) RX + AgF → R-F + AgX
  • This reaction is used to prepare alkyl fluorides (R-F) from alkyl halides (RX) using a metal fluoride like silver fluoride (AgF).
• (B) Finkelstein Reaction: (IV) RX + NaI → R-I + NaX
  • This reaction involves the halogen exchange, specifically replacing a halogen (X) in an alkyl halide (RX) with iodine (I) using sodium iodide (NaI).
• (C) Sandmeyer's Reaction: (I) C₆H₅NH₂ + NaNO₂ + HX + Cu₂X₂ → C₆H₅X + N₂
  • This reaction converts aromatic amines (C₆H₅NH₂) to aryl halides (C₆H₅X) via diazonium salts, using sodium nitrite (NaNO₂), an acid (HX), and a copper(I) halide (Cu₂X₂).
• (D) Wurtz Reaction: (II) 2RX + 2Na → R-R + 2NaX
  • This reaction couples two alkyl halides (RX) using sodium metal (Na) in dry ether to form a higher alkane (R-R).

Therefore, the correct matching is: A-III, B-IV, C-I, D-II