The combustion of methane (CH4) can be represented by the balanced chemical equation:
CH4 + 2O2 → CO2 + 2H2O.
To find the mass of methane required to produce 22 g of CO2, we proceed as follows:
Step 1: Determine the molar mass of CO2
Molar mass of CO2 = C + 2(O) = 12.0 + 2(16.0) = 44.0 g/mol.
Step 2: Calculate the moles of CO2 produced
Moles of CO2 = mass/molar mass = 22 g / 44.0 g/mol = 0.5 mol.
Step 3: Use the stoichiometry of the reaction to find moles of CH4
According to the balanced equation, 1 mole of CH4 produces 1 mole of CO2. Therefore, 0.5 mol of CO2 requires 0.5 mol of CH4.
Step 4: Determine the mass of CH4
Molar mass of CH4 = C + 4(H) = 12.0 + 4(1.0) = 16.0 g/mol.
Mass of CH4 = moles × molar mass = 0.5 mol × 16.0 g/mol = 8 g.
The mass of methane required is 8 g,
CH4 + 2O2 → CO2 + 2H2O
Moles of CO2 produced:
\[ \frac{22}{44} = 0.5 \, \text{mol} \]
Required moles of CH4:
\[ 0.5 \, \text{mol} \times 16 \, \text{g/mol} = 8 \, \text{g} \]
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,