Step 1: Understanding the Concept:
This is a first-order linear differential equation. We need to rearrange it into the standard form \( \frac{dy}{dx} + P(x)y = Q(x) \) and then find the Integrating Factor (I.F.).
Step 2: Key Formula or Approach:
1. Standard form: \( \frac{dy}{dx} + y \cdot \tan x = \frac{\sec^3 x}{\sqrt{\tan x}} \).
2. I.F. \( = e^{\int \tan x \, dx} = e^{\ln|\sec x|} = \sec x \).
Step 3: Detailed Explanation:
1. Rewrite the equation:
\[ \frac{dy}{dx} + y \frac{(\tan x)^{3/2}}{\sqrt{\tan x}} = \frac{\sec^3 x}{\sqrt{\tan x}} \implies \frac{dy}{dx} + y \tan x = \frac{\sec^3 x}{\sqrt{\tan x}} \]
2. Multiply by I.F. (\( \sec x \)):
\[ \frac{d}{dx}(y \sec x) = \frac{\sec^4 x}{\sqrt{\tan x}} \]
3. Integrate both sides:
\[ y \sec x = \int \frac{(1 + \tan^2 x) \sec^2 x}{\sqrt{\tan x}} dx \]
Let \( t = \tan x, dt = \sec^2 x \, dx \):
\[ y \sec x = \int (t^{-1/2} + t^{3/2}) dt = 2\sqrt{t} + \frac{2}{5}t^{5/2} + C \]
\[ y \sec x = 2\sqrt{\tan x} + \frac{2}{5}(\tan x)^{5/2} + C \]
4. Use \( y(\pi/4) = \frac{6\sqrt{2}}{5} \):
\[ \frac{6\sqrt{2}}{5} \cdot \sqrt{2} = 2(1) + \frac{2}{5}(1) + C \implies \frac{12}{5} = \frac{12}{5} + C \implies C = 0 \]
5. Find \( y(\pi/3) \):
\[ y \cdot 2 = 2(3^{1/4}) + \frac{2}{5}(3^{5/4}) = 2 \cdot 3^{1/4} + \frac{2 \cdot 3 \cdot 3^{1/4}}{5} = 3^{1/4} (2 + \frac{6}{5}) = \frac{16}{5} 3^{1/4} \]
\[ y = \frac{8}{5} 3^{1/4} \]
Step 4: Final Answer:
The value of \( y(\pi/3) \) is \( \frac{8}{5} \cdot 3^{1/4} \).