Question:

If the percentage change in the radius of a sphere is \(2\%\), then find the percentage change in the volume of the sphere.

Updated On: Apr 6, 2026
  • \(2\%\)
  • \(4\%\)
  • \(6\%\)
  • \(8\%\)
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The Correct Option is C

Solution and Explanation

Concept: The volume of a sphere is given by \[ V = \frac{4}{3}\pi r^3 \] Thus, volume is proportional to the cube of the radius: \[ V \propto r^3 \] For small percentage changes, the percentage change in a quantity raised to a power follows \[ \frac{\Delta V}{V} = 3 \frac{\Delta r}{r} \] Step 1: {\color{red}Use the relation between percentage changes.} \[ \%\Delta V = 3 \times \%\Delta r \] Step 2: {\color{red}Substitute the given percentage change in radius.} \[ \%\Delta V = 3 \times 2\% \] \[ \%\Delta V = 6\% \] Hence, the percentage change in the volume of the sphere is \[ \boxed{6\%} \]
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