Step 1: Analyze the sequence. The sequence is given as: \[ x_n = \sum_{k=1}^{n} \frac{1}{\sqrt{k}} - 2(\sqrt{n} - 1). \] The term \( 2(\sqrt{n} - 1) \) is a term that grows like \( 2\sqrt{n} \) as \( n \) increases, and the sum \( \sum_{k=1}^{n} \frac{1}{\sqrt{k}} \) grows like \( 2\sqrt{n} \) for large \( n \).
Step 2: Behavior of the sequence for large \( n \). We approximate the sequence for large \( n \): \[ x_n \sim \sum_{k=1}^{n} \frac{1}{\sqrt{k}} - 2\sqrt{n}. \] Using the asymptotic approximation for the sum, we have: \[ \sum_{k=1}^{n} \frac{1}{\sqrt{k}} \sim 2\sqrt{n} - 1. \] Thus, \( x_n \) behaves like: \[ x_n \sim 2\sqrt{n} - 1 - 2\sqrt{n} = -1. \] This suggests that the sequence is bounded and converges to \( -1 \).
Step 3: Monotonicity. Given that \( x_n \) decreases as \( n \) increases, the sequence is monotonically decreasing. Thus, the correct answer is \( \boxed{(B)} \).
Let \( (X_1, X_2, X_3) \) follow the multinomial distribution with the number of trials being 100 and the probability vector \( \left( \frac{3}{10}, \frac{1}{10}, \frac{3}{5} \right) \).
Then \( E(X_2 | X_3 = 40) \) equals:
Let \( X_1, \dots, X_5 \) be a random sample from \( N(\theta, 6) \), where \( \theta \in \mathbb{R} \), and let \( c(\theta) \) be the Cramer-Rao lower bound for the variances of unbiased estimators of \( \theta \) based on the above sample. Then \( 15 \cdot \inf_{\theta \in \mathbb{R}} c(\theta) \) equals _________ (answer in integer).
An electricity utility company charges ₹7 per kWh. If a 40-watt desk light is left on for 10 hours each night for 180 days, what would be the cost of energy consumption? If the desk light is on for 2 more hours each night for the 180 days, what would be the percentage-increase in the cost of energy consumption?
In the context of the given figure, which one of the following options correctly represents the entries in the blocks labelled (i), (ii), (iii), and (iv), respectively?

A bag contains Violet (V), Yellow (Y), Red (R), and Green (G) balls. On counting them, the following results are obtained:
(i) The sum of Yellow balls and twice the number of Violet balls is 50.
(ii) The sum of Violet and Green balls is 50.
(iii) The sum of Yellow and Red balls is 50.
(iv) The sum of Violet and twice the number of Red balls is 50.
Which one of the following Pie charts correctly represents the balls in the bag?