Question:

Let \(X\) be a single observation from a distribution having a probability density function \(f_\theta\), \(\theta \in \Theta\). For testing \(H_0: \theta = 1\) against \(H_1: \theta \neq 1\), under which of the following options a uniformly most powerful test of level \(0.05\) exists?

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A UMP test for a two sided hypothesis can exist only when the parameter also fixes the boundary of the support of \(X\), because then one side of the alternative is detected for free.
Updated On: Aug 3, 2026
  • \[ f_\theta(x) = \begin{cases} \dfrac{1}{\theta} & \text{if } 0 < x < \theta \\ 0 & \text{otherwise} \end{cases} ; \quad \Theta = (0, \infty) \]
  • \[ f_\theta(x) = \begin{cases} e^{-(x-\theta)} & \text{if } x > \theta \\ 0 & \text{otherwise} \end{cases} ; \quad \Theta = (-\infty, \infty) \]
  • \[ f_\theta(x) = \begin{cases} \dfrac{1}{\theta} e^{-x/\theta} & \text{if } x > 0 \\ 0 & \text{otherwise} \end{cases} ; \quad \Theta = (0, \infty) \]
  • \[ f_\theta(x) = \begin{cases} \dfrac{1}{\theta} e^{-(x-1)/\theta} & \text{if } x > 1 \\ 0 & \text{otherwise} \end{cases} ; \quad \Theta = (0, \infty) \]
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The Correct Option is A, B

Solution and Explanation

Step 1: When does a UMP two-sided test exist?
Only when \(\theta\) controls the boundary of the support, so one direction is caught for free.
Step 2: (A) Uniform(0,\(\theta\)).
\(x>1\) proves \(\theta>1\) for free; add \(x<0.05\) for the other side. UMP exists. TRUE.
Step 3: (B) shifted exponential support \((\theta,\infty)\).
\(x<1\) proves \(\theta<1\) for free; add \(x>c\) tail. UMP exists. TRUE.
Step 4: (C) Exponential(\(\theta\)), support \((0,\infty)\) fixed.
No free direction, no UMP. FALSE.
Step 5: (D) support \((1,\infty)\) fixed regardless of \(\theta\).
Same issue as (C), no UMP. FALSE.
Final Answer: \[ \boxed{\text{(A) and (B)}} \]
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