Step 1: Understanding the Concept:
This problem requires finding the median \( b \) of a continuous random variable \( X \) defined by its probability density function (PDF) over a given range.
Step 2: Detailed Explanation:
Let us analyze the given continuous probability density function:
\[ f(x) = 6x(1-x) \quad \text{for } 0 \le x \le 1 \]
The condition \( P(X b) \) means that the value \( b \) splits the entire probability distribution into two equal halves.
Since the total area under any valid PDF is \( 1 \), this condition simplifies to:
\[ P(X \le b) = \int_{0}^{b} f(x) \, dx = 0.5 \]
Let us solve this using two different approaches:
- Approach 1: Using Symmetry (Conceptual and Fast)
Notice the algebraic structure of \( f(x) \):
\[ f(1-x) = 6(1-x)(1 - (1-x)) = 6(1-x)x = f(x) \]
This confirms that the probability density function is perfectly symmetric about the midpoint of its domain \( [0, 1] \), which is \( x = 0.5 \).
For any continuous symmetric distribution on a closed interval, the median must lie exactly at the midpoint of symmetry.
Therefore, \( b = 0.5 = 1/2 \).
- Approach 2: Using Integration (Mathematical Proof)
Set up the integral:
\[ \int_{0}^{b} 6x(1-x) \, dx = 0.5 \]
\[ 6 \int_{0}^{b} (x - x^2) \, dx = 0.5 \]
\[ 6 \left[ \frac{x^2}{2} - \frac{x^3}{3} \right]_{0}^{b} = 0.5 \]
\[ 3b^2 - 2b^3 = 0.5 \implies 4b^3 - 6b^2 + 1 = 0 \]
Let us test if \( b = 1/2 \) is a root of this cubic equation:
\[ 4\left(\frac{1}{2}\right)^3 - 6\left(\frac{1}{2}\right)^2 + 1 = 4\left(\frac{1}{8}\right) - 6\left(\frac{1}{4}\right) + 1 = \frac{1}{2} - \frac{3}{2} + 1 = -1 + 1 = 0 \]
This mathematical proof confirms that \( b = 1/2 \) is indeed the correct median.
Step 3: Final Answer:
The value of \( b \) is \( 1/2 \).
Therefore, the correct choice is Option (A).