Let \(x_1, x_2, \dots, x_n\) be observations which have a variance \(\sigma_x^2\). Each \(x_i\) is changed to \(a x_i - h\), where \(a\) and \(h\) are positive constants, then the new series will have variance:
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Exam Tip:
Effects of transformations on variance:
• Adding \(c\): Variance unchanged.
• Subtracting \(c\): Variance unchanged.
• Multiplying by \(c\): Variance multiplied by \(c^2\).
Step 1: Understanding the Concept:
Variance is affected by changes in scale but not by changes in location.
Adding or subtracting a constant does not change the variance.
Multiplying by a constant multiplies the variance by the square of that constant. Step 2: Key Formula or Approach:
If \(y_i = a x_i - h\), then:
\[
\text{Var}(Y) = \text{Var}(aX - h) = a^2 \text{Var}(X) = a^2 \sigma_x^2
\]
Step 3: Detailed Explanation:
The constant \(h\) does not affect the variance because it is a location parameter.
The variance is multiplied by \(a^2\).
So, the new variance is \(a^2 \sigma_x^2\). Step 4: Final Answer:
Therefore, option (B) is correct.