Step 1: Check option (A).
For \(X_1\sim Exp(\theta)\), where \(\theta\) is the scale parameter,
\[
P(X_1>x)=e^{-x/\theta}
\]
Therefore,
\[
E(T_1)=P(X_1>2)=e^{-2/\theta}
\]
Hence, \(T_1\) is an unbiased estimator of \(e^{-2/\theta}\).
So, option (A) is true.
Step 2: Find a complete sufficient statistic.
For a random sample from \(Exp(\theta)\), the joint density depends on the sample through
\[
S=X_1+X_2
\]
Thus,
\[
S=X_1+X_2
\]
is sufficient for \(\theta\). Also, \(S\sim Gamma(2,\theta)\), and this gamma family is complete.
Hence, \(S\) is a complete sufficient statistic.
Step 3: Apply Rao-Blackwell theorem.
Since \(T_1\) is unbiased for \(e^{-2/\theta}\), the UMVUE is
\[
E(T_1\mid S)
\]
where
\[
S=X_1+X_2
\]
Given \(S=s\), \(X_1\) is uniformly distributed on \((0,s)\).
Therefore,
\[
E(T_1\mid S=s)=P(X_1>2\mid S=s)
\]
If \(s\leq 2\), then
\[
P(X_1>2\mid S=s)=0
\]
If \(s>2\), then
\[
P(X_1>2\mid S=s)=\frac{s-2}{s}
\]
Thus,
\[
E(T_1\mid S)
=
\max\left\{0,\frac{S-2}{S}\right\}
\]
Since \(S=X_1+X_2\),
\[
E(T_1\mid S)
=
\max\left\{0,\frac{X_1+X_2-2}{X_1+X_2}\right\}=T_2
\]
Hence, \(T_2\) is the UMVUE of \(e^{-2/\theta}\).
So, option (B) is true.
Step 4: Check option (C).
Since \(T_1\) is an indicator random variable with
\[
P(T_1=1)=e^{-2/\theta},
\]
we get
\[
Var(T_1)=e^{-2/\theta}\left(1-e^{-2/\theta}\right)
\]
This is not always less than or equal to
\[
\frac{2}{\theta}e^{-4/\theta}
\]
for all \(\theta>0\).
Hence, option (C) is false.
Step 5: Check option (D).
The statistic \((X_1,X_2)\) is sufficient, but it is not complete.
For example, a non-zero function such as
\[
h(X_1,X_2)=X_1-X_2
\]
has expectation
\[
E(X_1-X_2)=0
\]
for every \(\theta>0\), but \(h(X_1,X_2)\) is not almost surely zero.
Hence, \((X_1,X_2)\) is not complete.
So, option (D) is false.
Step 6: Final conclusion.
The true statements are
\[
\boxed{(A)\text{ and }(B)}
\]