Let the solution curve y = y(x) of the differential equation (4 + x2)dy – 2x(x2 + 3y + 4)dx = 0 pass through the origin. Then y(2) is equal to _______.
The correct answer is 12
(4 + x2) dy – 2x(x2 + 3y + 4)dx = 0
\(⇒\frac{dy}{dx}=(\frac{6x}{x^2+4})y+2x\)
\(⇒\frac{dy}{dx}−(\frac{6x}{x^2+4})y=2x\)
I.F. \(= e^{−3 In(x^2+4)}=\frac{1}{(x^2+4)^3}\)
\(So, \frac{y}{(x^2+4)^3}=∫\frac{2x}{(x^2+4)^3}dx+c\)
\(⇒y=−\frac{1}{2}(x^2+4)+c(x^2+4)^3\)
When x = 0, y = 0 gives
\(c=\frac{1}{32}\)
So, for x = 2,y = 12
Let $y=y(x)$ be the solution of the differential equation $\left(x^2-3 y^2\right) d x+3 x y d y=0, y(1)=1$.Then $6 y^2( e )$ is equal to
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A differential equation is an equation that contains one or more functions with its derivatives. The derivatives of the function define the rate of change of a function at a point. It is mainly used in fields such as physics, engineering, biology and so on.
The first-order differential equation has a degree equal to 1. All the linear equations in the form of derivatives are in the first order. It has only the first derivative such as dy/dx, where x and y are the two variables and is represented as: dy/dx = f(x, y) = y’
The equation which includes second-order derivative is the second-order differential equation. It is represented as; d/dx(dy/dx) = d2y/dx2 = f”(x) = y”.
Differential equations can be divided into several types namely