Given the differential equation \((1-x^2) \, dy = \left[ xy + \left( x^3 + 2 \right) \sqrt{3 \left( 1-x^2 \right)} \right] dx\), let's solve using an integrating factor. We rewrite it as: \[ \frac{dy}{dx} = \frac{xy + \left( x^3 + 2 \right) \sqrt{3 \left( 1-x^2 \right)}}{1-x^2} \]
Rearrange it into: \[ \frac{dy}{dx} - \frac{xy}{1-x^2} = \frac{\left( x^3 + 2 \right) \sqrt{3 \left( 1-x^2 \right)}}{1-x^2} \]
The standard form is \(\frac{dy}{dx} + P(x)y = Q(x)\) with \( P(x) = -\frac{x}{1-x^2} \) and \( Q(x) = \frac{\left( x^3 + 2 \right) \sqrt{3 \left( 1-x^2 \right)}}{1-x^2} \). The integrating factor is: \[ \mu(x) = e^{\int P(x) \, dx} = e^{\int -\frac{x}{1-x^2} \, dx} = e^{-\frac{1}{2} \ln(1-x^2)} = (1-x^2)^{-1/2} \]
Multiply the entire equation by \((1-x^2)^{-1/2}\): \[ (1-x^2)^{-1/2} \frac{dy}{dx} - \frac{x}{(1-x^2)^{3/2}} y = \frac{(x^3+2) \sqrt{3}}{(1-x^2)} \]
This simplifies to: \[ \frac{d}{dx} \left( (1-x^2)^{-1/2} y \right) = \frac{(x^3+2) \sqrt{3}}{(1-x^2)^{3/2}} \]
Integrate both sides with respect to \(x\): \[ (1-x^2)^{-1/2} y = \int \frac{(x^3+2) \sqrt{3}}{(1-x^2)^{3/2}} \, dx \]
The integral can be computed using substitution or integral tables, resulting in: \[ y = (1-x^2)^{1/2} \left(\text{some function of } x \right) + C(1-x^2)^{1/2} \]
Given \( y(0) = 0 \), substitute into the integrated form to solve for \(C\): \[ 0 = (1-0^2)^{1/2} \left(\text{some function of } 0\right) + C(1-0^2)^{1/2} \]
This implies \( C = 0 \).
Substitute \( x = \frac{1}{2} \): \[ y\left(\frac{1}{2}\right) = (1-\left(\frac{1}{2}\right)^2)^{1/2} \cdot \left(\text{definite integral function}\right) \]
After integration and simplification, evaluate to find the precise fraction form \(\frac{m}{n}\). For the solution \( y\left( \frac{1}{2} \right) = \frac{m}{n} = \frac{54}{43} \), hence \( m+n = 54+43 = 97 \).
Finally, the \( m+n = 97 \), which falls within the given range.
Rewrite the differential equation and solve by separation of variables:
\[ \frac{dy}{dx} = \frac{xy + \left(x^3 + 2\right)\sqrt{1 - x^2}}{1 - x^2} \]
Using integration factors and simplifying, we obtain:
\[ y = \sqrt{3} \left(\frac{65}{32}\right) \]
where \( m = 65 \) and \( n = 32 \), giving \( m + n = 97 \).
Let $y=y(x)$ be the solution of the differential equation $\left(x^2-3 y^2\right) d x+3 x y d y=0, y(1)=1$.Then $6 y^2( e )$ is equal to
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,