To solve the given problem, we need to determine the equivalence class of the point \((1, -1)\) using the relation \(R =\{( P , Q ) | P\) and \(Q\) are at the same distance from the origin \(\}\).
\(d = \sqrt{1^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2}\)
\(\sqrt{x^2 + y^2} = \sqrt{2}\)
\(x^2 + y^2 = 2\)
\(S = \{(x, y) \mid x^2 + y^2 = 2\}\)
Therefore, the equivalence class of the point \((1, -1)\) is the set of points \((x, y)\) such that \(x^2 + y^2 = 2\). This corresponds to the correct answer:
\(S = \{(x, y) \mid x^2 + y^2 = 2\}\)
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]
A relation in mathematics defines the relationship between two different sets of information. If two sets are considered, the relation between them will be established if there is a connection between the elements of two or more non-empty sets. Therefore, we can say, ‘A set of ordered pairs is defined as a relation.’
Read Also: Relation and Function
There are 8 main types of relations which are:
There are two ways by which a relation can be represented-
The roster form and set-builder for for a set integers lying between -2 and 3 will be-
I= {-1,0,1,2}
I= {x:x∈I,-2<x<3}