Let p, q, r be three statements such that the truth value of
\((p \wedge q) \rightarrow (\sim q \vee r)\) is F. Then the truth values of p, q, r are respectively :
\((p \wedge q) \rightarrow (\sim q \vee r)\) is F. Then the truth values of p, q, r are respectively :
Show Hint
- T, F, T
- F, T, F
- T, T, T
- T, T, F
The Correct Option is D
Solution and Explanation
Here \(A = p \wedge q\) and \(B = \sim q \vee r\).
For A to be true: \(p \wedge q = T\), so p = T and q = T.
For B to be false: \(\sim q \vee r = F\), so both \(\sim q = F\) and r = F. Since q = T, \(\sim q = F\) holds, and r = F.
Hence (p, q, r) = (T, T, F).
Answer: (4) T, T, F
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