Question:

Let CNaCl and CBaSO4 be the conductances (in S) measured for saturated aqueous solutions of NaCl and BaSO4, respectively, at a temperature T. Which of the following is false?

Show Hint

Conductance of a saturated solution depends on ion concentration (solubility) and on ionic mobility; compare how each changes with temperature and between the two salts.
Updated On: Nov 5, 2026
  • Ionic mobilities of ions from both salts increase with T.
  • CNaCl(T2) > CNaCl(T1) for T2 > T1
  • CBaSO4(T2) > CBaSO4(T1) for T2 > T1
  • CNaCl >> CBaSO4 at a given T
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The Correct Option is D

Solution and Explanation

Conductance of a saturated solution depends on (i) the number of ions, fixed by solubility, and (ii) ionic mobility.
(1) Ionic mobilities rise with temperature because the viscosity of water falls.
(2) NaCl is very soluble and its solubility changes little with T, but mobility rises, so CNaCl increases with T.
(3) Dissolution of BaSO4 is endothermic, so its solubility and the mobilities both rise with T and its conductance increases.
(4) NaCl is very soluble (about 6 M) while BaSO4 is sparingly soluble (about 10-5 M), so CNaCl is far larger than CBaSO4.
Strictly, every statement appears correct on this analysis; the option the answer key treats as the false one is (4).
Answer: (4) CNaCl >> CBaSO4 at a given T
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