Let a = i + 2j -2k and b = 2i - j - 2k be two vectors. If the orthogonal projection vector of a on b is x and orthogonal projection vector of b on a is y then |x - y| =
4/9 √10
4/9 √26
8/9 √10
8/9√26
Given vectors $a = i+2j-2k$ and $b = 2i-j-2k$, we need to find the magnitude of the difference between their orthogonal projections.
1. Compute Orthogonal Projection of $a$ on $b$ ($x$):
$x = \frac{a \cdot b}{|b|^2} b$
$a \cdot b = (1)(2) + (2)(-1) + (-2)(-2) = 4$
$|b|^2 = 2^2 + (-1)^2 + (-2)^2 = 9$
$x = \frac{4}{9}(2i-j-2k) = \frac{8}{9}i - \frac{4}{9}j - \frac{8}{9}k$
2. Compute Orthogonal Projection of $b$ on $a$ ($y$):
$y = \frac{b \cdot a}{|a|^2} a$
$b \cdot a = 4$ (same as above)
$|a|^2 = 1^2 + 2^2 + (-2)^2 = 9$
$y = \frac{4}{9}(i+2j-2k) = \frac{4}{9}i + \frac{8}{9}j - \frac{8}{9}k$
3. Calculate Difference $x - y$:
$x - y = \left(\frac{8}{9} - \frac{4}{9}\right)i + \left(-\frac{4}{9} - \frac{8}{9}\right)j + \left(-\frac{8}{9} - (-\frac{8}{9})\right)k$
$= \frac{4}{9}i - \frac{12}{9}j + 0k = \frac{4}{9}i - \frac{4}{3}j$
4. Find Magnitude of $x - y$:
$|x-y| = \sqrt{\left(\frac{4}{9}\right)^2 + \left(-\frac{4}{3}\right)^2} = \sqrt{\frac{16}{81} + \frac{16}{9}}$
$= \sqrt{\frac{16}{81} + \frac{144}{81}} = \sqrt{\frac{160}{81}} = \frac{4\sqrt{10}}{9}$
Final Answer:
The magnitude of the difference is ${\dfrac{4\sqrt{10}}{9}}$
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