Question:

Let A be a \(3\times3\) matrix such that \(A^2-5A+7I=O\).
Statement - I : \(A^{-1}=\frac{1}{7}(5I-A)\).
Statement - II : The polynomial \(A^3-2A^2-3A+I\) can be reduced to \(5(A-4I)\).
Then :

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Use \(A^2=5A-7I\); multiply by \(A^{-1}\) for Statement I and reduce the cubic using \(A^2\) for Statement II.
Updated On: Nov 11, 2026
  • Statement-I is true, but Statement-II is false.
  • Statement-I is false, but Statement-II is true.
  • Both the statements are true.
  • Both the statements are false.
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The Correct Option is C

Solution and Explanation

Statement I: \(A^2-5A+7I=O\). Multiply by \(A^{-1}\): \(A-5I+7A^{-1}=O\), so \(A^{-1}=\frac{1}{7}(5I-A)\). True.
Statement II: \(A^2=5A-7I\), so \(A^3=5A^2-7A=5(5A-7I)-7A=18A-35I\).
\(A^3-2A^2-3A+I=(18A-35I)-2(5A-7I)-3A+I=5A-20I=5(A-4I)\). True.
Both statements are true.
Answer: (3) Both the statements are true.
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