Question:

Let \(A\) be a \(3 \times 3\) matrix such that \(\operatorname{adj}(A)=\left[\begin{array}{ccc}25 & 0 & 100 \\ 0 & 4 & 3 \\ 0 & 100 & 100\end{array}\right]\), then determinant of \(A\) is

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For an n x n matrix, |adj A| = |A|^(n-1); compute |adj A| first.
Updated On: Nov 12, 2026
  • 25
  • 50
  • 100
  • 1000
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The Correct Option is B

Solution and Explanation

For a 3 x 3 matrix, \(|\operatorname{adj}(A)|=|A|^{2}\).
Expand along the first column: \(|\operatorname{adj}A| = 25\,(4\cdot 100-3\cdot 100) = 25\cdot 100 = 2500\).
So \(|A|^2=2500\), giving \(|A|=50\) (taking the positive value, the only one among the options).
Answer: (2) 50
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