Question:
Let \( A = [a_{ij}] \) be a square matrix of order 2 with entries either 0 or 1. Let \( E \) be the event that \( A \) is an invertible matrix. Then the probability \( P(E) \) is:
Let \( A = [a_{ij}] \) be a square matrix of order 2 with entries either 0 or 1. Let \( E \) be the event that \( A \) is an invertible matrix. Then the probability \( P(E) \) is:
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To determine the probability of an event involving matrices, count the total number of possible matrices and the favorable cases (invertible or non-invertible) and calculate the ratio.
Updated On: Mar 25, 2026
- \( \frac{3}{16} \)
- \( \frac{3}{8} \)
- \( \frac{5}{8} \)
- \( \frac{1}{8} \)
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The Correct Option is C
Solution and Explanation
A 2x2 matrix is invertible if its determinant is non-zero. We count the total number of 2x2 matrices with entries 0 or 1, which is \( 2^4 = 16 \). Then, we count the number of matrices that are not invertible (i.e., their determinant is zero) and subtract that from the total to find the number of invertible matrices. The probability \( P(E) \) is the ratio of invertible matrices to the total number of matrices.
Final Answer: \( \frac{5}{8} \).
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