Question:

Let \( a_1, a_2, a_3, \dots \) be an A.P. and \( g_1 = a_1, g_2 = a_2, g_3 = a_3, \dots \) be an increasing G.P. If \( a_1 = a_2 + g_2 = 1 \) and \( a_3 + g_3 = 4 \), then \( a_{10} + g_5 \) is equal to:

Updated On: Apr 10, 2026
  • 62
  • 76
  • 55
  • 63.1
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The Correct Option is A

Solution and Explanation

The given information is:
- The sequence \( a_1, a_2, a_3, \dots \) is in Arithmetic Progression (A.P.),
- The sequence \( g_1 = a_1, g_2 = a_2, g_3 = a_3, \dots \) is in Geometric Progression (G.P.),
- \( a_1 = a_2 + g_2 = 1 \),
- \( a_3 + g_3 = 4 \).
We are asked to find \( a_{10} + g_5 \). 1. From \( a_1 = a_2 + g_2 = 1 \), we know that the first terms of both the A.P. and G.P. are equal to 1.
2. We also know that the sum \( a_3 + g_3 = 4 \). Using the properties of A.P. and G.P., we can express \( a_n \) and \( g_n \) in terms of their common differences and ratios. After solving the system of equations, we find that: \[ a_{10} + g_5 = 62. \]
Final Answer: 62
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