Question:

\(t_{100\%}\) is the time required for 100% completion of a reaction, while \(t_{1/2}\) is the time required for 50% completion of the reaction. Which of the following correctly represents the relation between \(t_{100\%}\) and \(t_{1/2}\) for zero order and first order reactions respectively

Updated On: Apr 10, 2026
  • \(t_{100\%} = 2t_{1/2}, \quad t_{100\%} = \infty\)
     

  • \(t_{100\%} = 2t_{1/2} \quad \text{and} \quad t_{100\%} = \infty\)
     

  • \(t_{100\%} = 2t_{1/2} \quad \text{and} \quad t_{100\%} = (2t_{1/2})^2\)

  • \(t_{100\%} = \infty \quad \text{and} \quad t_{100\%} = 2t_{1/2}\)

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The Correct Option is B

Solution and Explanation

Concept:

  • Zero order reaction \[ t_{1/2} = \frac{[A]_0}{2k} \] \[ t_{100\%} = \frac{[A]_0}{k} \] Thus, \[ t_{100\%} = 2t_{1/2} \]
  • First order reaction \[ t_{1/2} = \frac{0.693}{k} \] In first order reactions, reactant concentration approaches zero asymptotically, so the reaction never reaches exactly \(100\%\) completion. Thus, \[ t_{100\%} = \infty \]

\[ \boxed{t_{100\%} = 2t_{1/2} \text{ and } t_{100\%} = \infty} \]

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