\(A = \begin{bmatrix} 0 & -2 \\[0.3em] 2 & 0 \end{bmatrix}\)
\(A^2 = \begin{bmatrix} 0 & -2 \\[0.3em] 2 & 0 \end{bmatrix} \begin{bmatrix} 0 & -2 \\[0.3em] 2 & 0 \end{bmatrix}\)=\( \begin{bmatrix} -4 & 0 \\[0.3em] 0 & -4 \end{bmatrix}\)=\(−4I\)
\(M = A_2 + A_4 + A_6 + … + A^{20}\)
\(= –4I + 16l – 64I + …\) upto \(10\) terms
\(= –I [4 – 16 + 64 … + \)upto \(10\) terms\(]\)
\(=−I⋅4[\frac {(−4)^{10}−1}{−4−1}]\)
\(=\frac 45(2^{20}−1)I\)
\(= A – 4A + 16A + …\) upto \(10\) terms
\(=A[\frac {(−4)^{10}−1}{−4−1}]\)
\(=−(\frac {2^{20}−1}{5})A\)
\(N^2=\frac {(2^{20}−1)^2}{2^5}\)
\(A^2=−\frac {4}{25}(2^{20}−1)^2t\)
\(MN^{2}=−\frac {16}{125}(2^{20}−1)^3 \)
\(I=KI\ (K≠±1)\)
\((MN^2)^T = (KI)^T = KI\)
∴ \(A\) is correct
So, the correct option is (A): a non-identity symmetric matrix.
Let \[ R = \begin{pmatrix} x & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & z \end{pmatrix} \text{ be a non-zero } 3 \times 3 \text{ matrix, where} \]
\[ x = \sin \theta, \quad y = \sin \left( \theta + \frac{2\pi}{3} \right), \quad z = \sin \left( \theta + \frac{4\pi}{3} \right) \]
and \( \theta \neq 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi \). For a square matrix \( M \), let \( \text{trace}(M) \) denote the sum of all the diagonal entries of \( M \). Then, among the statements:
Which of the following is true?
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A matrix is a rectangular array of numbers, variables, symbols, or expressions that are defined for the operations like subtraction, addition, and multiplications. The size of a matrix is determined by the number of rows and columns in the matrix.
