Let \[ R = \begin{pmatrix} x & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & z \end{pmatrix} \text{ be a non-zero } 3 \times 3 \text{ matrix, where} \]
\[ x = \sin \theta, \quad y = \sin \left( \theta + \frac{2\pi}{3} \right), \quad z = \sin \left( \theta + \frac{4\pi}{3} \right) \]
and \( \theta \neq 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi \). For a square matrix \( M \), let \( \text{trace}(M) \) denote the sum of all the diagonal entries of \( M \). Then, among the statements:
Which of the following is true?
This problem requires us to analyze two statements regarding a non-zero \( 3 \times 3 \) diagonal matrix \( R \). The diagonal entries of \( R \) are given as trigonometric functions of an angle \( \theta \).
1. Trace of a Matrix: The trace of a square matrix is the sum of its diagonal elements, denoted as \( \text{trace}(M) = \sum_{i} M_{ii} \).
2. Trigonometric Identities: We will use the sum-of-angles formula for sine:
\[ \sin(A + B) = \sin A \cos B + \cos A \sin B \]
3. Adjoint of a Matrix: For an \( n \times n \) matrix \( M \), the second adjoint (adjoint of the adjoint) is given by the formula:
\[ \text{adj}(\text{adj}(M)) = (\det M)^{n-2} M \]
4. Determinant of a Diagonal Matrix: The determinant of a diagonal matrix is the product of its diagonal entries.
Analysis of Statement 1: Trace(R) = 0
Step 1: Write down the expression for the trace of matrix \( R \).
The matrix is \( R = \begin{pmatrix} x & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & z \end{pmatrix} \). The trace is the sum of its diagonal entries:
\[ \text{trace}(R) = x + y + z \]
Step 2: Substitute the given trigonometric definitions for \( x, y, \) and \( z \).
\[ \text{trace}(R) = \sin \theta + \sin \left( \theta + \frac{2\pi}{3} \right) + \sin \left( \theta + \frac{4\pi}{3} \right) \]
Step 3: Expand the terms using the sine sum-of-angles formula.
We know the values:
Expanding \( y \) and \( z \):
\[ y = \sin \left( \theta + \frac{2\pi}{3} \right) = \sin \theta \cos \left( \frac{2\pi}{3} \right) + \cos \theta \sin \left( \frac{2\pi}{3} \right) = -\frac{1}{2} \sin \theta + \frac{\sqrt{3}}{2} \cos \theta \] \[ z = \sin \left( \theta + \frac{4\pi}{3} \right) = \sin \theta \cos \left( \frac{4\pi}{3} \right) + \cos \theta \sin \left( \frac{4\pi}{3} \right) = -\frac{1}{2} \sin \theta - \frac{\sqrt{3}}{2} \cos \theta \]
Step 4: Sum the terms to find the trace.
\[ \text{trace}(R) = \sin \theta + \left( -\frac{1}{2} \sin \theta + \frac{\sqrt{3}}{2} \cos \theta \right) + \left( -\frac{1}{2} \sin \theta - \frac{\sqrt{3}}{2} \cos \theta \right) \] \[ \text{trace}(R) = \left( \sin \theta - \frac{1}{2} \sin \theta - \frac{1}{2} \sin \theta \right) + \left( \frac{\sqrt{3}}{2} \cos \theta - \frac{\sqrt{3}}{2} \cos \theta \right) \] \[ \text{trace}(R) = (0) \sin \theta + (0) \cos \theta = 0 \]
This result holds for any value of \( \theta \). Therefore, the statement "Trace(R) = 0" is true.
Analysis of Statement 2: If \( \text{trace}(\text{adj}(\text{adj}(R))) = 0 \), then \( R \) has exactly one non-zero entry.
Step 1: Find the expression for \( \text{trace}(\text{adj}(\text{adj}(R))) \).
For a \( 3 \times 3 \) matrix \( R \), the second adjoint is \( \text{adj}(\text{adj}(R)) = (\det R)^{3-2} R = (\det R) R \).
Since \( R \) is a diagonal matrix, its determinant is the product of its diagonal elements:
\[ \det R = xyz \]
So, the second adjoint is:
\[ \text{adj}(\text{adj}(R)) = (xyz) R = (xyz) \begin{pmatrix} x & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & z \end{pmatrix} = \begin{pmatrix} x^2yz & 0 & 0 \\ 0 & xy^2z & 0 \\ 0 & 0 & xyz^2 \end{pmatrix} \]
The trace of this matrix is:
\[ \text{trace}(\text{adj}(\text{adj}(R))) = x^2yz + xy^2z + xyz^2 = xyz(x + y + z) \]
Step 2: Evaluate the condition \( \text{trace}(\text{adj}(\text{adj}(R))) = 0 \).
From our analysis of Statement 1, we know that \( x + y + z = 0 \). Substituting this into the trace expression:
\[ \text{trace}(\text{adj}(\text{adj}(R))) = xyz(0) = 0 \]
This shows that the hypothesis of Statement 2, \( \text{trace}(\text{adj}(\text{adj}(R))) = 0 \), is always true for any \( \theta \).
Step 3: Check the conclusion of Statement 2: "R has exactly one non-zero entry."
The statement is an implication: If A is true, then B must be true. We have shown A is always true. Now we must check if B is always true. Let's test a value for \( \theta \) that is allowed by the problem conditions, e.g., \( \theta = \frac{\pi}{6} \).
\[ x = \sin\left(\frac{\pi}{6}\right) = \frac{1}{2} \] \[ y = \sin\left(\frac{\pi}{6} + \frac{2\pi}{3}\right) = \sin\left(\frac{5\pi}{6}\right) = \frac{1}{2} \] \[ z = \sin\left(\frac{\pi}{6} + \frac{4\pi}{3}\right) = \sin\left(\frac{3\pi}{2}\right) = -1 \]
For this value of \( \theta \), the matrix \( R \) has diagonal entries \( \frac{1}{2}, \frac{1}{2}, -1 \). All three entries are non-zero. This provides a counterexample to the conclusion that \( R \) must have exactly one non-zero entry.
Since the hypothesis of the implication is always true but the conclusion is not always true, the implication itself is false.
Based on the analysis:
Therefore, only the first statement is true.
Calculate the trace of \( R \): Since \( x + y + z = \sin \theta + \sin \left( \theta + \frac{2\pi}{3} \right) + \sin \left( \theta + \frac{4\pi}{3} \right) = 0 \), we have:
\[ \text{trace}(R) = x + y + z = 0. \]
Thus, statement (I) is true.
Examine statement (II): \(\text{adj}(R) = \begin{pmatrix} yz & 0 & 0 \\ 0 & xz & 0 \\ 0 & 0 & xy \end{pmatrix}\). Therefore,
\[ \text{adj}(\text{adj}(R)) = \begin{pmatrix} x^2yz & 0 & 0 \\ 0 & xy^2z & 0 \\ 0 & 0 & xyz^2 \end{pmatrix}. \]
The trace of \(\text{adj}(\text{adj}(R))\) is \( xyz(x + y + z) = 0 \), even if \( R \) has more than one non-zero entry.
Thus, statement (II) is false.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
A matrix is a rectangular array of numbers, variables, symbols, or expressions that are defined for the operations like subtraction, addition, and multiplications. The size of a matrix is determined by the number of rows and columns in the matrix.
