Question:

Krishna walked 20 m towards the north. Then he turned right and walked 30 m. Then he turned right and walked 35 m. Then he turned left and walked 15 m. Finally he turns left and went 15 m. In which direction and how many meters is Krishna compared to from the starting position ?

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Use coordinate geometry for direction-distance problems. Assign East as positive x, North as positive y. Calculate net displacement at the end using Pythagoras if needed.
Updated On: Mar 26, 2026
  • 15 m West
  • 30 m East
  • 30 m West
  • 15 m East
  • 45 m East
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Solution and Explanation


Step 1: Understanding the Concept:

Direction and distance problem. Track x (East-West) and y (North-South) coordinates.

Step 2: Detailed Explanation:

Start at (0,0), facing North.
Step 1: Walk 20m North $\to$ (0, 20).
Step 2: Turn right (now facing East), walk 30m $\to$ (30, 20).
Step 3: Turn right (now facing South), walk 35m $\to$ (30, $-15$).
Step 4: Turn left (now facing East), walk 15m $\to$ (45, $-15$).
Step 5: Turn left (now facing North), walk 15m $\to$ (45, 0).
Final position: (45, 0). East displacement = 45m, North displacement = 0m. Krishna is 45 m East of the start.

Step 3: Final Answer:

Krishna is 45 m East of the starting position.
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