Concept:
To determine whether \(x\) is negative, we check whether the given conditions uniquely fix the sign of \(x\).
Important properties:
• If \(x^2>0\), then \(x\neq0\), but \(x\) may be positive or negative.
• If \(x^3\geq0\), then \(x\geq0\).
Step 1: Checking Statement (I).
Given:
\[
x^2>0
\]
This means:
\[
x\neq0
\]
Possible values:
\[
x=2 \quad (\text{positive})
\]
or
\[
x=-2 \quad (\text{negative})
\]
Both satisfy the condition.
So, Statement (I) alone is not sufficient.
Step 2: Checking Statement (II).
Given:
\[
x^3\geq0
\]
Since cube preserves the sign:
\[
x\geq0
\]
Thus, \(x\) cannot be negative.
So the answer to “Is \(x\) negative?” is definitely No.
Hence, Statement (II) alone is sufficient.