Question:
Iodine on reaction with concentrated nitric acid gives three products X, Y and Z. The sum of oxidation numbers of the central atoms in X, Y and Z is
Iodine on reaction with concentrated nitric acid gives three products X, Y and Z. The sum of oxidation numbers of the central atoms in X, Y and Z is
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Iodine is oxidized to iodic acid \((HIO_3)\) by concentrated nitric acid.
Updated On: Jun 18, 2026
- 5
- 6
- 7
- 4
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The Correct Option is C
Solution and Explanation
Concept:
Iodine reacts with concentrated nitric acid producing iodic acid along with nitrogen oxides and water.
Step 1: Write the reaction.
\[ I_2 + 10HNO_3 \rightarrow 2HIO_3 + 10NO_2 + 4H_2O \] Products are: \[ HIO_3,\quad NO_2,\quad H_2O \]
Step 2: Determine oxidation numbers.
For \(HIO_3\), \[ I=+5 \] For \(NO_2\), \[ N=+4 \] For \(H_2O\), \[ O=-2 \]
Step 3: Find the sum.
Considering the central atoms: \[ (+5)+(+4)+(-2) \] \[ =7 \] Hence, \[ \boxed{7} \]
Step 1: Write the reaction.
\[ I_2 + 10HNO_3 \rightarrow 2HIO_3 + 10NO_2 + 4H_2O \] Products are: \[ HIO_3,\quad NO_2,\quad H_2O \]
Step 2: Determine oxidation numbers.
For \(HIO_3\), \[ I=+5 \] For \(NO_2\), \[ N=+4 \] For \(H_2O\), \[ O=-2 \]
Step 3: Find the sum.
Considering the central atoms: \[ (+5)+(+4)+(-2) \] \[ =7 \] Hence, \[ \boxed{7} \]
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