Question:
\(\int_{-\pi/2}^{\pi/2} |\sin x| dx\) is
\(\int_{-\pi/2}^{\pi/2} |\sin x| dx\) is
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For even symmetry, double the integral from 0 to limit.
Updated On: Apr 15, 2026
- 2
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- \(\pi/2\)
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The Correct Option is A
Solution and Explanation
Concept:
\(|\sin x|\) is symmetric.
Step 1: Split integral.
\[ =2\int_0^{\pi/2} \sin x dx \]
Step 2: Evaluate.
\[ =2[-\cos x]_0^{\pi/2}=2(1)=2 \]
Step 1: Split integral.
\[ =2\int_0^{\pi/2} \sin x dx \]
Step 2: Evaluate.
\[ =2[-\cos x]_0^{\pi/2}=2(1)=2 \]
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