Question

Instructions: Seven students, Priya, Ankit, Raman, Sunil, Tony, Deepak and Vicky, take a series of tests. No two students get similar marks. Vicky always scores more than Priya. Priya always scores more than Ankit. Each time, either Raman scores the highest and Tony gets the least, or alternatively Sunil scores the highest and Deepak or Ankit scores the least.

If Raman is ranked second and Ankit is ranked first, which of the following must be true?

• A. Sunil is ranked third
• B. Tony is ranked third
• C. Priya is ranked sixth
• D. None of these

Hint:

Ankit ranked first would break the fixed rule that Priya always outscores Ankit, since no rank can beat first place.

Answer 1

The Correct Option is D

Step 1: Check whether this situation is even possible.
The rules state Priya always scores more than Ankit, which means Priya's rank must always be better (a smaller number) than Ankit's rank.

Step 2: Apply the given ranks.
Here, Ankit is placed at rank 1, the best possible rank. Since no rank can be better than 1, it is impossible for Priya to rank better than Ankit in this situation, directly breaking the rule that Priya must always outscore Ankit.

Step 3: Conclude.
Because the starting premise itself contradicts one of the fixed rules of the puzzle, none of the specific outcomes in options A, B or C can be relied upon as “must be true” conclusions drawn from consistent rules.

Step 4: Final Answer.
Since the scenario is not logically consistent with the given conditions, the safest and correct choice is option D, none of these.