Question:
Instructions: A numerical machine accepts two values X and Y. At every step, it updates the values as X = X times Y, and Y = Y + 1. The machine stops as soon as X becomes greater than or equal to N.
Using the same values as before (X = 3, Y = 2, N = 100), what is the final value of Y?
Instructions: A numerical machine accepts two values X and Y. At every step, it updates the values as X = X times Y, and Y = Y + 1. The machine stops as soon as X becomes greater than or equal to N.
Using the same values as before (X = 3, Y = 2, N = 100), what is the final value of Y?
Using the same values as before (X = 3, Y = 2, N = 100), what is the final value of Y?
Show Hint
Y simply increases by 1 each step, so its final value is the starting Y plus the number of steps run.
Updated On: Jul 15, 2026
- 4
- 5
- 6
- 20
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The Correct Option is C
Solution and Explanation
Step 1: Reuse the earlier simulation.
Tracking Y alongside X: start Y = 2; after step 1, Y = 3; after step 2, Y = 4; after step 3, Y = 5; after step 4, Y = 6, at which point X = 360 ≥ 100 and the machine stops.
Step 2: Final Answer.
The final value of Y, at the moment the machine stops, is 6, so option C is correct.
Tracking Y alongside X: start Y = 2; after step 1, Y = 3; after step 2, Y = 4; after step 3, Y = 5; after step 4, Y = 6, at which point X = 360 ≥ 100 and the machine stops.
Step 2: Final Answer.
The final value of Y, at the moment the machine stops, is 6, so option C is correct.
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