Question:

In \(\triangle ABC\), if \(\cot A, \cot B\) and \(\cot C\) are in AP, then \(a^2, b^2\) and \(c^2\) are in

Show Hint

Use identity: \(\cot A = \frac{b^2+c^2-a^2}{4\Delta}\) for triangle problems.
Updated On: Apr 16, 2026
  • HP
  • AP
  • GP
  • None of these
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Concept: \[ \cot A = \frac{b^2 + c^2 - a^2}{4\Delta} \] If \(\cot A, \cot B, \cot C\) are in AP: \[ 2\cot B = \cot A + \cot C \] Substituting gives: \[ a^2, b^2, c^2 \text{ are in AP} \]
Was this answer helpful?
0
0