Question

In the system shown in figure $M₁ > M₂$ and pulley and threads are ideal. System is held at rest by thread BC. Just after thread BC is burnt.

• A. Acceleration $M₁$ and $M₂$ will be upward
• B. Magnitude of acceleration of both masses will be $\fracM₁-M₂M₁+M₂g$
• C. Acceleration of $M₁$ and $M₂$ will be equal to zero
• D. Acceleration of $M₁$ will be equal to zero, while that of $M₂$ will be $\fracM₁-M₂M₂g$ upward

Hint:

For an Atwood machine, $a = \fracM₁-M₂M₁+M₂g$.

Answer 1

The Correct Option is B

Step 1: After burning BC, the system is a standard Atwood machine.

Step 2: Acceleration $a = \fracM₁-M₂M₁+M₂g$, with $M₁$ moving down and $M₂$ moving up.