Step 1: Check reflexivity.
A relation $R$ is reflexive if $(a,a) \in R$ for all $a$.
Here, $R = \{(1,2), (2,3), (3,4), (4,5), (5,6)\}$.
No pair is of the form $(a,a)$.
Hence, $R$ is **not reflexive**.
Step 2: Check symmetry.
If $(a,b) \in R$, then for symmetry $(b,a) \in R$.
Example: $(1,2) \in R$, but $(2,1) \notin R$.
So, $R$ is **not symmetric**.
Step 3: Check transitivity.
If $(a,b) \in R$ and $(b,c) \in R$, then $(a,c)$ should be in $R$.
Example: $(1,2) \in R$ and $(2,3) \in R$, so $(1,3)$ should be in $R$.
But $(1,3) \notin R$.
Hence, $R$ is **not transitive**.
Step 4: Conclusion.
The relation $R$ is not reflexive, not symmetric, and not transitive.
Thus, the correct answer is (C).
A relation \( R = \{(a, b) : a = b - 2, b \geq 6 \} \) is defined on the set \( \mathbb{N} \). Then the correct answer will be:
The principal value of the \( \cot^{-1}\left(-\frac{1}{\sqrt{3}}\right) \) will be: