Question:
In the reaction, ${PH_3 + HI ? PH_4I, PH_3}$ is behaving like
In the reaction, ${PH_3 + HI ? PH_4I, PH_3}$ is behaving like
Updated On: Jun 7, 2022
- dehydrating agent
- oxidising agent
- Lewis base
- Lewis acid.
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The Correct Option is C
Solution and Explanation
Phosphine $(PH_3)$ is feebly basic and forms salts with mineral acids under anhydrous conditions.
${$\underset{\mathrm{Phosphine}}{{PH_3}}$ + HX -> $\underset{\mathrm{Phosphonium \, halide \\ (X=Cl,Br,I)}}{{PH^+_4 X^-}}$ }$
${$\underset{\mathrm{Phosphine}}{{PH_3}}$ + HX -> $\underset{\mathrm{Phosphonium \, halide \\ (X=Cl,Br,I)}}{{PH^+_4 X^-}}$ }$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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